Question

How do you solve `16- 2c = - 20- 20c`?

Answer 1

`c = -2`

Explanation:

Begin with the equation

`16 - 2c = -20 -20c`

Use the additive inverse to move the terms with the variables to the same side

`16 - 2c + 20c = -20 cancel(-20c) cancel (+20c)`

`16 + 18c = -20`

Use the additive inverse to move the constant terms to the same side

`cancel16 + 18c cancel(-16)= -20 -16`

`18c = -36`

Use the multiplicative inverse to isolate the variable

`(cancel(18)c)/cancel(18) = (-36)/18`

Solution `c = -2`.