How do you solve 16- 2c = - 20- 20c?

Jan 20, 2018

$c = - 2$

Explanation:

Begin with the equation

$16 - 2 c = - 20 - 20 c$

Use the additive inverse to move the terms with the variables to the same side

$16 - 2 c + 20 c = - 20 \cancel{- 20 c} \cancel{+ 20 c}$

$16 + 18 c = - 20$

Use the additive inverse to move the constant terms to the same side

$\cancel{16} + 18 c \cancel{- 16} = - 20 - 16$

$18 c = - 36$

Use the multiplicative inverse to isolate the variable

$\frac{\cancel{18} c}{\cancel{18}} = \frac{- 36}{18}$

Solution $c = - 2$.