Question

How do you solve `16^ { x } = \frac { 1} { 4}`?

Answer 1

`x=-1/2`

Explanation:

`16^x=(4^2)^x=4^(2x)" and "1/4=4^(-1)`

`rArr4^(2x)=4^(-1)`

`"since the bases on both sides are 4 equate the exponents"`

`rArr2x=-1rArrx=-1/2`