How do you solve #16(z+3)=4(z+9)#?

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Answer 1 · 2015-12-03T07:55:31

#color(blue)(z=-1#

#color(blue)(16)(z+3)=color(green)(4)(z+9)#

#color(blue)(16) * (z) + color(blue)(16) * (3)=color(green)(4 )* (z) + color(green)(4) * (9)#

#16z +48=4z +36#

#16z -4z =36 -48#

#12z =-12#

#z=(-12)/12#

#color(blue)(z=-1#