How do you solve #17> 4c - 3\geq - 19#?

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Answer 1 · 2017-03-29T18:50:33

See the entire solution process below:

First, add #color(red)(3)# to each segment of the system of inequalities to isolate the #c# term while keeping the system balanced:

#17 + color(red)(3) > 4c - 3 + color(red)(3) >= -19 + color(red)(3)#

#20 > 4c - 0 >= -16#

#20 > 4c >= -16#

Now, divide each segment by #color(red)(4)# to solve for #c# while keeping the system balanced:

#20/color(red)(4) > (4c)/color(red)(4) >= -16/color(red)(4)#

#5 > (color(red)(cancel(color(black)(4)))c)/cancel(color(red)(4)) >= -4#

#5 > c >= -4#