How do you solve #19-6x=4x+11#?

1 Answer
Feb 1, 2018

See a solution process below:

Explanation:

First, add #color(red)(6x)# and subtract #color(blue)(11)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#19 - color(blue)(11) - 6x + color(red)(6x) = 4x + color(red)(6x) + 11 - color(blue)(11)#

#8 - 0 = (4 + color(red)(6))x + 0#

#8 = 10x#

Now, divide each side of the equation by #color(red)(10)# to solve for #x# while keeping the equation balanced:

#8/color(red)(10) = (10x)/color(red)(10)#

#4/5 = (color(red)(cancel(color(black)(10)))x)/cancel(color(red)(10))#

#4/5 = x#

#x = 4/5#