How do you solve #-19c + - 86= - 675#?

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Answer 1 · 2017-09-21T03:16:41

#c=31#

To solve for c, first isolate the term(s) that.contain c, in this the term would be #-19c#. Adding #86# on both sides:

#-19c + cancel(-86) + cancel(86) = -675 + 86#
#implies##-19c = -589#

To isolate #c#, divide both sides of the equation by #-19#

#cancel((-19)c)/cancel(-19) = (-589)/-19#
#c = 589/19# since a negative number divided by a negative number is positive.

Dividing, we get:
#c = 31#

Answer 2 · 2017-09-21T03:22:29

#c = 31#

Add 86 to both sides:

#-19c -86 + 86 = -675 + 86#

# -19c = -589#

Divide both sides by -19:

# (cancel(-19c))/cancel(-19) = -589/-19#

#c = 31#