How do you solve #-19z - 0.4= - 29z + 2.8#?

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Answer 1 · 2017-11-28T02:55:32

See a solution process below:

First, add #color(red)(0.4)# and #color(blue)(29z)# to each side of the equation to isolate the #z# term while keeping the equation balanced:

#color(blue)(29z) - 19z - 0.4 + color(red)(0.4) = color(blue)(29z) - 29z + 2.8 + color(red)(0.4)#

#(color(blue)(29) - 19)z - 0 = 0 + 3.2#

#10z = 3.2#

Now, divide each side of the equation by #color(red)(10)# to solve for #z# while keeping the equation balanced:

#(10z)/color(red)(10) = 3.2/color(red)(10)#

#(color(red)(cancel(color(black)(10)))z)/cancel(color(red)(10)) = 0.32#

#z = 0.32#