How do you solve #2.3= 2^ { \frac { x } { 9} + 1} + 1#?

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Answer 1 · 2017-11-18T12:11:54

Solution: #x ~~ -5.59 #

#2.3 =2 ^(x/9+1) +1 or 2 ^(x/9+1) =2.3-1 # or

#2^(x/9)*2^1 =1.3 or 2^(x/9)=1.3/2 or 2^(x/9)=0.65 #

Taking log on both sides we get ,

#x/9log 2 =log(0.65) or x/9 =log(0.65) /log2# or

#x/9=-0.621488 or x=9*(-0.621488)

or #x ~~ -5.59(2dp) #

Solution: #x ~~ -5.59(2dp) # [Ans]