How do you solve #2(3-x)=16(x+1)#?

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Answer 1 · 2018-06-05T03:20:59

#x=-5/9#

Let's distribute the #2# and the #16# to their respective terms. We get

#6-2x=16x+16#

Let's subtract #6# from both sides to get

#-2x=16x+10#

Next, we can subtract #16x# from both sides to get

#-18x=10#

Lastly, we can divide both sides by #-18# to get

#x=-10/18#, which can be simplified to

#x=-5/9#

Hope this helps!