How do you solve #2( 3n + 64) = 16- n#?

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Answer 1 · 2017-12-03T21:32:33

#n=-16#

Distribute the things on the left side first.

#2(3n+64)=16-n#

#6n+128=16-n#

Move all variables to one side, and the whole numbers on the other. (Note: When you do something to one side, you must also do it to the other side)

#6n+128-128+n=16-n+n-128#

#6n+n=16-128#

#7n=-112#

Now isolate for n by dividing both sides by 7

#7n/7 = -112/7#

#n=-16#