How do you solve #2< 3x - 1\leq 14#?

1 Answer
Jim G.
Apr 18, 2018

#x in(1,5]#

Explanation:

#"add 1 to all 3 intervals"#

#2color(red)(+1)< 3xcancel(-1)cancel(color(red)(+1))<=14color(red)(+1)#

#rArr3<3x<=15#

#"divide all 3 intervals by 3"#

#rArr1< x<=5" is the solution"#

#x in(1,5]larrcolor(blue)"in interval notation"#

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