How do you solve #2.4x + 13\leq 5#?

Question

292 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-08T20:39:32

#x <= -3 1/3#

Here's how I did it:

We solve inequalities similarly to equations.

Let's subtract #13# from both sides of the inequality:
#2.4x + 13 quadcolor(red)(-quad13) quad<= quad5 quadcolor(red)(-quad13)#

#2.4x <= -8#

Now divide both sides by #2.4#:
#(2.4x)/(color(red)2.4) <= (-8)/color(red)2.4#

#x <= -3 1/3#

Hope this helps!