How do you solve #2( 5^ { 2x - 9} ) = 250#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer CW Dec 2, 2016 #x=6# Explanation: #2(5^(2x-9))=250# #=> 5^(2x-9)=125# #=> 5^(2x-9)=5^3# #=> 2x-9=3# #=> 2x=12# #=> x=6# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1033 views around the world You can reuse this answer Creative Commons License