# How do you solve 2+ 6v = - 8- 4v ?

Nov 29, 2017

$v = - 1$

#### Explanation:

Original: $\text{ } 2 + 6 v = - 8 - 4 v$

(add $4 v$ to both sides) $\text{ } 2 + 10 v = - 8$

(subtract $2$ from both sides) $\text{ } 10 v = - 10$

(divide $10$ from both sides) $\text{ } v = - 1$

So it may be more helpful if you see something like this and are stuck to imagine the different operations of the equation as individual parts. For example,

$\left(+ 2\right) , \left(+ 6 v\right) = \left(- 8\right) , \left(- 4 v\right)$

In order to "get rid" of the different separated parts of this equation, just do the opposite operation to the opposite side. For example, to cancel out $\left(- 4 v\right)$, just add $\left(+ 4 v\right)$ to $\left(+ 6 v\right)$. You should end up with the same answer of $- 1$ after you have divided $- 10$ by $10$.

Nov 29, 2017

$v = - 1$

#### Explanation:

$2 + 6 v = - 8 - 4 v$

First begin by adding $8$ to each side:

$10 + 6 v = - 4 v$

Second, subtract $6 v$ from each side because you want to get the $v$ variables on one side of the equation:

$10 = - 10 v$

Lastly, divide each side by $- 10$ so $v$ can be by itself on one side of the equation

$- 1 = v$