How do you solve #-2(b+5)=-6#?

1 Answer
Alan P.
Jun 15, 2015

#-2(b+5) = -6 rArr b= -2#

Explanation:

#-2(b+5) = -6#
expand the left side by multiplying through:
#rarr##color(white)("XXXX")##-2b -10 = -6#
divide everything by #(-2)#
#rarr##color(white)("XXXX")##b+5 = 3#
subtract #(5)# from both sides
#rarr##color(white)("XXXX")##b = -2#

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