How do you solve 2( c - 4) + 8= \frac { 1} { 2} ( 6c + 20)?

Jun 18, 2018

$c = - 10$

Explanation:

$\text{distribute brackets on both sides}$

$2 c \cancel{- 8} \cancel{+ 8} = 3 c + 10$

$2 c = 3 c + 10$

$\text{subtract "2c" from both sides}$

$0 = c + 10$

$\text{subtract 10 from both sides}$

$- 10 = c \Rightarrow c = - 10$

Jun 18, 2018

$c = - 10$

Explanation:

If $2 \left(c - 4\right) + 8 = \frac{1}{2} \left(6 c + 20\right)$
we have
$4 \left(c - 4\right) + 16 = 6 c + 20$
$4 c - 16 + 16 = 6 c + 20$
$4 c = 16 c + 20$
Move all the c terms to the left and the constants to the right of the equality sign:
$4 c - 6 c = 20$
$- 2 c = 20$
$c = - 10$