How do you solve #2\cdot 2^ { - 2b - 10} + 1= 79#?

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Answer 1 · 2018-04-20T13:43:36

#b=-1/2((ln78)/(ln2)+9)#

Given: #2*2^(-2b-10)+1=79#.

#=>2^(-2b-10+1)+1=79#

#=>2^(-2b-9)+1=79#

#2^(-2b-9)=78#

Take natural logarithms on both sides.

#ln(2^(-2b-9))=ln78#

#(-2b-9)ln2=ln78#

#-2b-9=(ln78)/(ln2)#

#-2b=(ln78)/(ln2)+9#

#b=-1/2((ln78)/(ln2)+9)#