How do you solve #2( d - 4) = .3d + 4- 2+ .6d#?

1 Answer
Jun 15, 2018

#d = 100/11# or about #9.09# (rounded to nearest hundredth's place)

Explanation:

#2(d-4) = 0.3d + 4 - 2 + 0.6d#

First, combine the like terms on the right hand side of the equation:
#2(d-4) = (0.3d + 0.6d) + (4 - 2)#

#2(d-4) = 0.9d + 2#

Now use the distributive property (shown below) to simplify/expand the left hand side:
cdn.virtualnerd.com

Following this image, we know that:
#color(blue)(2(d-4) = (2 * d) + (2 * -4) = 2d - 8)#

Put this expression back into the equation:
#2d - 8 = 0.9d + 2#

Subtract #color(blue)(0.9d)# from both sides:
#2d - 8 quadcolor(blue)(-quad0.9d) = 0.9d + 2 quadcolor(blue)(-quad0.9d)#

#1.1d - 8 = 2#

Add #color(blue)8# to both sides:
#1.1d - 8 quadcolor(blue)(+quad8) = 2 quadcolor(blue)(+quad8)#

#1.1d = 10#

Divide both sides by #color(blue)(1.1)#:
#(1.1d)/color(blue)(1.1) = 10/color(blue)1.1#

Therefore,
#d = 100/11# or about #9.09# (rounded to nearest hundredth's place)

Hope this helps!