How do you solve #2\geq 8- 2k#?

1 Answer
Apr 14, 2017

#k>=3#

Explanation:

#color(blue)"Isolate" -2k# on the right side and collect numeric values on the left side.

subtract 8 from both sides.

#2-8>=cancel(8)cancel(-8)-2k#

#rArr-6>=-2k#

#"divide both sides by " -2#

[Remember to reverse the sign when dividing/multiplying by a negative quantity. ]

#(-6)/(-2)<=(cancel(-2) k )/cancel(-2)larrcolor(red)" reverse sign"#

#rArr3<=krArrk>=3" is the solution"#