How do you solve #2\geq 8- 2k#?
1 Answer
Apr 14, 2017
Explanation:
#color(blue)"Isolate" -2k# on the right side and collect numeric values on the left side.subtract 8 from both sides.
#2-8>=cancel(8)cancel(-8)-2k#
#rArr-6>=-2k#
#"divide both sides by " -2# [Remember to reverse the sign when dividing/multiplying by a negative quantity. ]
#(-6)/(-2)<=(cancel(-2) k )/cancel(-2)larrcolor(red)" reverse sign"#
#rArr3<=krArrk>=3" is the solution"#