How do you solve -2=-(n-8)?

1 Answer
Apr 29, 2017

See the solution process below:

Explanation:

First, multiply each side of the equation by $\textcolor{red}{- 1}$ to eliminate the negative from each side of the equation while keeping the equation balanced:

$\textcolor{red}{- 1} \cdot - 2 = \textcolor{red}{- 1} \cdot - \left(n - 8\right)$

$2 = n - 8$

Now, add $\textcolor{red}{8}$ to each side of the equation to solve for $n$ while keeping the equation balanced:

$2 + \textcolor{red}{8} = n - 8 + \textcolor{red}{8}$

$10 = n - 0$

$10 = n$

$n = 10$