Question

How do you solve `(2\times \cos 2x ) ^ { 2} + 4\sin ^ { 2} 2x = 4`?

Answer 1

It is an identity and we solve as shown below.

Explanation:

`(2cos2x)^2+4sin^2 2x`

= `4cos^2 2x+4sin^2 2x`

= `4(cos^2 2x+sin^2 2x)`

= `4xx1`

= `4`