Question

How do you solve `2^x=10`?

Answer 1

`x = ln(10)/ln(2)`

Explanation:

Use any base logarithm on both sides. (I will use ln(x)):

`ln(2^x) = ln(10)`

Use the identity ln(a^b) = ln(a)b:

`ln(2)x = ln(10)`

Divide both sides by `ln(2)`:

`x = ln(10)/ln(2)`