How do you solve #2(x-3)^2 = 3#?
1 Answer
May 14, 2016
Explanation:
Divide both sides by
#(x-3)^2 = 3/2 = 6/4#
Take the square root of both ends, allowing either sign:
#x-3 = +-sqrt(6/4) = +-sqrt(6)/sqrt(4) = +-sqrt(6)/2#
Add
#x = 3+-sqrt(6)/2#
