How do you solve # –2(x – 3) ≥ 5 – (x + 3) #?

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Answer 1 · 2018-07-21T21:43:20

#x <= 4#

#-2(x-3) >= 5 - (x+3)#

Simplify both sides:
#-2x + 6 >= 5 - x - 3#

#-2x + 6 >= 2 - x#

Add #color(blue)(2x)# to both sides:
#-2x + 6 quadcolor(blue)(+quad2x) >= 2 - x quadcolor(blue)(+quad2x)#

#6 >= 2 + x#

Subtract #color(blue)2# from both sides:
#6 quadcolor(blue)(-quad2) >= 2 + x quadcolor(blue)(-quad2)#

#4 >= x#

Therefore,
#x <= 4#

Hope this helps!