How do you solve #2^(x−4)+10=22#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer harsh s. Aug 8, 2017 #x~~7.5849625# Explanation: #2^(x-4)+10=22# #=> 2^(x-4)=12# #=>x-4=log(12)/log(2)# #=>x=log_2(12)+4# #=>x~~7.5849625# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2024 views around the world You can reuse this answer Creative Commons License