# How do you solve 2^x= 4^(x+1)?

##### 1 Answer
Aug 17, 2015

color(blue)(x=-2

#### Explanation:

${2}^{x} = {4}^{x + 1}$
We know that $4 = {2}^{2}$

So the expression can be written as:
${2}^{x} = {2}^{2 \cdot \left(x + 1\right)}$

${2}^{x} = {2}^{2 x + 2}$

Now as the bases are equal we equate the exponents to find $x$

$x = 2 x + 2$

$- 2 = 2 x - x$

color(blue)(x=-2