How do you solve 2(x-5)^2=30?

Oct 24, 2015

$x = \pm \sqrt{15} + 5$
$x \approx 8.87 , 1.13$

Explanation:

First lets divide both sides by $2$,
${\left(x - 5\right)}^{2} = 15$
Now square root both sides,
$x - 5 = \pm \sqrt{15}$
Now take away $5$ from both sides,
$x = \pm \sqrt{15} + 5$
Now evaluate:
$x \approx 8.87 , 1.13$