How do you solve #20( x - 3)^{2} = 625#?

1 Answer
EZ as pi
Sep 20, 2016

#x = 8.590 " or "x = -2.590#

Explanation:

Isolate the factor with #x#

#20(x-3)^2 = 625 " "larr# divide by 20

#(x-3)^2 = 625/20 = 31.25#

#x-3 = +-sqrt31.25" "larr# square root of both sides

#x = +sqrt31.25 +3 = 8.590#

or # x = -sqrt31.25 +3 = -2.590#

Related questions
Impact of this question
487 views around the world
You can reuse this answer
Creative Commons License