# How do you solve 20x + 19= 10x + 13?

Jul 25, 2018

$x = - \frac{3}{5}$

#### Explanation:

$20 x + 19 = 10 x + 13$

Subtract $\textcolor{b l u e}{10 x}$ from both sides:
$20 x + 19 \quad \textcolor{b l u e}{- \quad 10 x} = 10 x + 13 \quad \textcolor{b l u e}{- \quad 10 x}$

$10 x + 19 = 13$

Subtract $\textcolor{b l u e}{19}$ from both sides:
$10 x + 19 \quad \textcolor{b l u e}{- \quad 19} = 13 \quad \textcolor{b l u e}{- \quad 19}$

$10 x = - 6$

Divide both sides by $\textcolor{b l u e}{10}$:
$\frac{10 x}{\textcolor{b l u e}{10}} = \frac{- 6}{\textcolor{b l u e}{10}}$

$x = - \frac{6}{10}$

$x = - \frac{3}{5}$

Hope this helps!

Jul 25, 2018

$x = - \frac{3}{5}$

#### Explanation:

Let's get our $x$ terms on one side. We can start by subtracting $10 x$ from both sides to get

$10 x + 19 = 13$

Next, let's get our constants on the right. We can subtract $19$ from both sides to get

$10 x = - 6$

Dividing both sides by $10$, we get

$x = - \frac{6}{10}$ or $x = - \frac{3}{5}$

Hope this helps!