How do you solve #21>15+2a#?

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Answer 1 · 2018-07-24T18:36:05

#a < 3#

#21 > 15 + 2a#

Subtract #color(blue)15# from both sides:
#21 quadcolor(blue)(-quad15) > 15 + 2a quadcolor(blue)(-quad15)#

#6 > 2a#

Divide both sides by #color(blue)2#:
#6/color(blue)2 > (2a)/color(blue)2#

#3 > a#

#a < 3#

Hope this helps!