How do you solve #-22+ 3k + 6= - 28#?

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Answer 1 · 2016-11-07T13:03:35

-22 + 3k + 6 = -28
3k = -28 + 22 - 6
3k = -6 + (-6)
k = -12/3 = -4

Answer 2 · 2016-11-07T13:04:40

#k = -4#

Step 1) Combine like terms
Step 2) Solve for #k# keeping the equation balanced

#3k + (6 - 22) = -28#

#3k - 16 = - 28#

#3k - 16 + 16 = -28 + 16#

#3k = -12#

#(3k)/3 = -12/3#

#k = -4#

Answer 3 · 2016-11-07T13:09:48

#k=-4#

I will use brackets to show grouping. They serve no other purpose

Write as:

#""(6-22)+3k" "=" "-28#

#" "color(green)(-16+3k" "=" "-28)#

Add #color(red)(16)# to both sides

#" "color(green)(color(red)(16)-16+3k" "=" "color(red)(16)-28)#

#" "0+3k" "=" "-12#

Divide both sides by #color(red)(3)#

#color(green)(3k" "=" "-12" "->" "3/(color(red)(3)) k" "=" "-12/(color(red)(3))#

#" "k" "=" "-4#