Question

How do you solve `22=44(1-e^(2x))`?

Answer 1

I got: `x=(ln(1/2))/2=-0.34657`

Explanation:

Let us rearrange it as:
`1-e^(2x)=22/44`
`1-e^(2x)=1/2`
`e^(2x)=1-1/2`
`e^(2x)=1/2`
take the natural log of both sides:
`ln(e^(2x))=ln(1/2)`
`2xln(e)=ln(1/2)`
but `ln(e)=1`
so:
`2x=ln(1/2)`
`x=(ln(1/2))/2=-0.34657`