How do you solve #222\leq 6( 5x + 7)#?

Question

412 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-15T12:53:48

#x >= 6#

Step 1) Expand the terms within the parenthesis:

#222 <= (6*5x) + (6*7)#

#222 <= 30x + 42#

Step 2) Solve for x while keeping the inequality balanced:

#222 - 42 <+ 30x +42 - 42#

#180 <= 30x + 0#

#180 <= 30x#

#180/30 <= (30x)/30#

#6 <= 1x#

#6 <= x#

Step 3) Reverse the inequality to state in terms of #x#:

#x >= 6#