How do you solve #234+ 78x = 12x ^ { 2}#?

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Answer 1 · 2017-10-27T11:06:27

By arranging it

Your equation:

#-12x^2+78x+234=0#

Find Delta first:

#Delta = b^2-(4timesatimesc)#

#Delta=78^2 + (4times12times234)#

#Delta= 6084+11232 = 17316#

#(Delta)^(1/2) = 131.59#

Your solution

#x_1 = (-b-(Delta^0.5))/(2timesa)#

#x_1= (-78-131.59)/-24 =8.73#

#x_2 = (-b+(Delta^0.5))/(2timesa)#

#x_2= (-78+131.59)/(-24) = -2.23#