How do you solve #24x ^ { 2} - 6= 10x#?

1 Answer
Dec 19, 2016

#x = 3/4# and #x = -1/3#

Explanation:

First, we need to convert this to the normal form of a quadratic equation:

#24x^2 - 6 - color(red)(10x)= 10x - color(red)(10x)#

#24x^2 - 10x - 6 = 0#

Next to factor the quadratic we need to play with multiplies for 24 (1x24, 2x12, 3x8, 4x6) and multipliers for 6 (1x6, 2x3) to give us:

#(4x - 3)(6x + 2) = 0#

We can now solve each term for #0#:

Solution 1)

#4x - 3 = 0#

#4x - 3 + color(red)(3) = 0 + color(red)(3)#

#4x - 0 = 3#

#4x = 3#

#(4x)/color(red)(4) = 3/color(red)(4)#

#(color(red)(cancel(color(black)(4)))x)/color(red)(cancel(color(black)(4))) = 3/4#

#x = 3/4#

Solution 2)

#6x + 2 = 0#

#6x + 2 - color(red)(2) = 0 - color(red)(2)#

#6x + 0 = -2#

#6x = -2#

#(6x)/color(red)(6) = -2/color(red)(6)#

#(color(red)(cancel(color(black)(6)))x)/color(red)(cancel(color(black)(6))) = -1/3#

#x = -1/3#