How do you solve #26p ^ { 2} + 35p = 0#?

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Answer 1 · 2018-03-06T13:37:15

#p=0 and p=-35/26#

Factor out #p# giving:

#p(26p+35)=0#

So we have #p=0 and 26p+35=0#

Consider #26p+35=0#

Subtract 35 from both sides

#26p=-35#

Divide both sides by 26

#p=-35/26#
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#p=0 and p=-35/26#