How do you solve 27=3c-3(6-2c)?

Apr 16, 2018

$c = 5$

Explanation:

$27 = 3 c - 3 \left(6 - 2 c\right)$

Distribute:
$27 = 3 c - 18 + 6 c$

Combine $3 c$ and $6 c$:
$27 = 9 c - 18$

Add $18$ to both sides of the equation:
$27 \quad \textcolor{red}{+ \quad 18} = 9 c - 18 \quad \textcolor{red}{+ \quad 18}$

$45 = 9 c$

Divide both sides by $9$:
$\frac{45}{\textcolor{red}{9}} = \frac{9 c}{\textcolor{red}{9}}$

$5 = c$

Therefore, $c = 5$.

Hope this helps!