First, subtract #color(red)(10)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#28 - color(red)(10) > 10 - color(red)(10) - 9x#

#18 > 0 - 9x#

#18 > -9x#

Now, divide each side of the inequality by #color(blue)(-9)# to solve for #x# while keeping the inequality balanced. However, because we are multiplying or dividing and inequality by a negative number we must reverse the inequality operator:

#18/color(blue)(-9) color(red)(<) (-9x)/color(blue)(-9)#

#-2 color(red)(<) (color(red)(cancel(color(black)(-9)))x)/cancel(color(blue)(-9))#

#-2 < x#

To state the solution in terms of #x# we can reverse or "flip" the entire inequality:

#x > -2#