How do you solve #28+ x = 57#?

1 Answer
smendyka
Mar 4, 2018

See a solution process below:

Explanation:

Subtract #color(red)(28)# from each side of the equation to solve for #x# while keeping the equation balanced:

#28 - color(red)(28) + x = 57 - color(red)(28#

#0 + x = 29#

#x = 29#

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