How do you solve #29.8- 2w = 42#?

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Answer 1 · 2017-06-26T01:04:54

See a solution process below:

First, subtract #color(red)(29.8)# from each wide of the equation to isolate the #w# term while keeping the equation balanced:

#-color(red)(29.8) + 29.8 - 2w = -color(red)(29.8) + 42#

#0 - 2w = 12.2#

#-2w = 12.2#

Now, divide each side of the equation by #color(red)(-2)# to solve for #w# while keeping the equation balanced:

#(-2w)/color(red)(-2) = 12.2/color(red)(-2)#

#(color(red)(cancel(color(black)(-2)))w)/cancel(color(red)(-2)) = -6.1#

#w = -6.1#