# How do you solve 2b ^ { 2} - 20b - 5= 0?

Using quadratic formula to find roots of given quadratic equation: $2 {b}^{2} - 20 b - 5 = 0$ as follows
$b = \setminus \frac{- \left(- 20\right) \setminus \pm \setminus \sqrt{{\left(- 20\right)}^{2} - 4 \left(2\right) \left(- 5\right)}}{2 \left(2\right)}$
$= \setminus \frac{20 \setminus \pm 2 \setminus \sqrt{110}}{4}$
$= \setminus \frac{10 \setminus \pm \setminus \sqrt{110}}{2}$