How do you solve #2f ^ { 2} + 7f + 5= 0#?

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Answer 1 · 2017-11-28T02:42:00

See a solution process below:

First, factor the left side of the equation as:

#(2f + 5)(f + 1) = 0#

Now, solve each term on the left for #0# to find the solutions to the problem:

Solution 1:

#2f + 5 = 0#

#2f + 5 - color(red)(5) = 0 - color(red)(5)#

#2f + 0 = -5#

#2f = -5#

#(2f)/color(red)(2) = -5/color(red)(2)#

#(color(red)(cancel(color(black)(2)))f)/cancel(color(red)(2)) = -5/2#

#f = -5/2#

Solution 2:

#f + 1 = 0#

#f + 1 - color(red)(1) = 0 - color(red)(1)#

#f + 0 = -1#

#f = -1#

The Solution Is: #f = {-5/2, -1}#