How do you solve #2f ( 5f - 6) = 0#?

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Answer 1 · 2017-11-07T21:58:11

See a solution process below:

Because the left side of the equation is factored we can solve each term on the left for #0# to find the solutions to the problem:

Solution 1:

#2f = 0#

#(2f)/color(red)(2) = 0/color(red)(2)#

#(color(red)(cancel(color(black)(2)))f)/cancel(color(red)(2)) = 0#

#f = 0#

Solution 2:

#5f - 6 = 0#

#5f - 6 + color(red)(6) = 0 + color(red)(6)#

#5f - 0 = 6#

#5f = 6#

#(5f)/color(red)(5) = 6/color(red)(5)#

#(color(red)(cancel(color(black)(5)))f)/cancel(color(red)(5)) = 6/5#

#f = 6/5#

The Solutions Are: #f = 0# and #f = 6/5#