How do you solve #-2k ^ { 2} = 40#?

1 Answer
May 31, 2017

See a solution process below:

Explanation:

First, divide each side of the equation by #color(red)(-2)# to isolate #k^2# while keeping the equation balanced:

#(-2k^2)/color(red)(-2) = 40/color(red)(-2)#

#(color(red)(cancel(color(black)(-2)))k^2)/cancel(color(red)(-2)) = -20#

#k^2 = -20#

Next, we would take the square root of each side of the equation to solve for #k#. However, when dealing with real numbers you cannot take the square root of a negative number. Therefore, in the domain of real numbers there is no solution for this problem or the solution is the empty or null set or #{O/}#