How do you solve #2ln(3x)=4#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Lucy May 31, 2018 x=2.46 (2.d.p) Explanation: #2In(3x)=4# #2log_e(3x)=4# #log_e(3x)=2# #3x=e^2# #x=e^2/3# #x=2.46# (2.d.p) Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 3357 views around the world You can reuse this answer Creative Commons License