How do you solve #2ln3x+1=5#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Mia Nov 16, 2016 #x = e^2/3# Explanation: # " "# #2ln3x + 1 = 5# #" "# #rArr 2ln3x = 5-1# #" "# #rArr2ln3x = 4# #" "# #rArrln3x = 4/2# #" "# #rArrln3x = 2# #" "# #rArre^(ln3x) = e^2# #" "# #rArr 3x = e^2# #" "# #rArrx = e^2/3# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 2028 views around the world You can reuse this answer Creative Commons License