How do you solve # 2m + 18 >12 #?

1 Answer
Dec 24, 2016

Answer:

#color(red)(m) > -3#

Explanation:

First, isolate the #color(red)(m)# term on the left side of the inequality and the constants on the right side of the inequality while keeping he equation balanced:

#2color(red)(m) + 18 - color(blue)(18) > 12 - color(blue)(18)#

#2color(red)(m) + 0 > -6#

#2color(red)(m) > -6#

The next step is to solve for #m# while keeping the inequality balanced:

#(2color(red)(m))/color(blue)(2) > -6/color(blue)(2)#

#(color(blue)(cancel(color(black)(2)))color(red)(m))/cancel(color(blue)(2)) > -3#

#color(red)(m) > -3#