How do you solve  2m + 18 >12 ?

Dec 24, 2016

$\textcolor{red}{m} > - 3$

Explanation:

First, isolate the $\textcolor{red}{m}$ term on the left side of the inequality and the constants on the right side of the inequality while keeping he equation balanced:

$2 \textcolor{red}{m} + 18 - \textcolor{b l u e}{18} > 12 - \textcolor{b l u e}{18}$

$2 \textcolor{red}{m} + 0 > - 6$

$2 \textcolor{red}{m} > - 6$

The next step is to solve for $m$ while keeping the inequality balanced:

$\frac{2 \textcolor{red}{m}}{\textcolor{b l u e}{2}} > - \frac{6}{\textcolor{b l u e}{2}}$

$\frac{\textcolor{b l u e}{\cancel{\textcolor{b l a c k}{2}}} \textcolor{red}{m}}{\cancel{\textcolor{b l u e}{2}}} > - 3$

$\textcolor{red}{m} > - 3$