How do you solve #2sqrt(y+2) - 4=8#?

1 Answer
Jim G.
Apr 11, 2018

#y=34#

Explanation:

#"isolate "sqrt(y+2)" on the left side"#

#"add 4 to both sides"#

#rArr2sqrt(y+2)=12#

#"divide both sides by 2"#

#rArrsqrt(y+2)=6#

#"square both sides"#

#(sqrt(y+2))^2=6^2#

#rArry+2=36#

#"subtract 2 from both sides"#

#rArry=34#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#2sqrt36-4=(2xx6)-4=12-4=8=" right side"#

#rArry=34" is the solution"#

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