How do you solve #2sqrtx + 3 = 10#?

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Answer 1 · 2015-07-24T18:23:26

You isolate #sqrt(x)# on one side, then square both sides of the equation.

The first thing you need to do in order to solve this equation is isolate #sqrt(x)# on one side of the equation.

To do this, first add #-3# to both sides of the equation

#2sqrt(x) +cancel(3) - cancel(3) = 10 - 3#

#2sqrt(x) = 7#

Next, divide both sides of the equation by #2#

#(cancel(2) * sqrt(x))/cancel(2) = 7/2#

#sqrt(x) = 7/2#

To get the value of #x#, square both sides

#(sqrt(x))""^2 = (7/2)^2#

#x = color(green)(49/4)#